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Question

An inductor of inductance $L=400$ $mH$ and resistors of resistance ${R_1} = 2\Omega $ and ${R_2} = 2\Omega $ are connected to a battery of $emf$ $12$ $V$ as shown in the figure. The internal resistance of the battery is negligible. The switch $S$ is closed at $t=0.$ The potential drop across $L$ as a function of time is :

${{12} \over t}{e^{ - 3t}}V$
$6\left( {1 - {e^{ - t/0.2}}} \right)V$
$12{e^{ - 5t}}V$
$6{e^{ - 5t}}V$

Solution

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