The surface of a metal is illuminated with the light of $400$ $nm.$ The kinetic energy of the ejected photoelectrons was found to be $1.68$ $eV.$ The work function of the metal is : $\left( {hc = 1240eV.nm} \right)$
$1.41$ $eV$
$1.51$ $eV$
$1.68$ $eV$
$3.09$ $eV$
Solution
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