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Question

An electric dipole is placed as shown in the figure.

The electric potential (in 102 V) at point P due to the dipole is ($\in_0$ = permittivity of free space and $\frac{1}{4 \pi \epsilon_{0}}$ = K) :

$\left(\frac{5}{8}\right) \mathrm{qK}$
$\left(\frac{8}{5}\right) \mathrm{qK}$
$\left(\frac{8}{3}\right) \mathrm{qK}$
$\left(\frac{3}{8}\right) \mathrm{qK}$

Solution

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