The solution for $x$ of the equation $\int\limits_{\sqrt 2 }^x {{{dt} \over {t\sqrt {{t^2} - 1} }} = {\pi \over 2}} $ is - DASH

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Question

The solution for $x$ of the equation $\int\limits_{\sqrt 2 }^x {{{dt} \over {t\sqrt {{t^2} - 1} }} = {\pi \over 2}} $ is

${{\sqrt 3 } \over 2}$

$2\sqrt 2 $

$2$

None

Solution

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