A particle of mass $m$ executes simple harmonic motion with amplitude a and frequency $v.$ The average kinetic energy during its motion from the position of equilibrium to the end is
$2{\pi ^2}\,m{a^2}{v^2}$
${\pi ^2}\,m{a^2}{v^2}$
${1 \over 4}\,m{a^2}{v^2}$
$4{\pi ^2}m{a^2}{v^2}$
Solution
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