A point mass oscillates along the $x$-axis according to the law $x = {x_0}\,\cos \left( {\omega t - \pi /4} \right).$ If the acceleration of the particle is written as $a = A\,\cos \left( {\omega t + \delta } \right),$ then
$A = {x_0}{\omega ^2},\,\,\delta = 3\pi /4$
$A = {x_0},\,\,\delta = - \pi /4$
$A = {x_0}{\omega ^2},\,\,\delta = \pi /4$
$A = {x_0}{\omega ^2},\,\,\delta = - \pi /4$
Solution
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