The potential at a point $x$ (measured in $\mu \,m$) due to some charges situated on the $x$-axis is given by $V\left( x \right) = 20/\left( {{x^2} - 4} \right)$ volt The electric field $E$ at $x = 4\,\mu \,m$ is given by

Question

The potential at a point $x$ (measured in $\mu \,m$) due to some charges situated on the $x$-axis is given by $V\left( x \right) = 20/\left( {{x^2} - 4} \right)$ volt
The electric field $E$ at $x = 4\,\mu \,m$ is given by

$(10/9)$ volt / $\mu $ $m$ and in the $ + ve$ $x$ direction

$\left( {5/3} \right)$ volt/ $\mu $ $m$ and in the $-ve$ $x$ direction

$\left( {5/3} \right)$ volt/$\mu $ $m$ and in the $+ve$ $x$ direction

$\left( {10/9} \right)$ volt/ $\mu \,m$ and in the $-ve$ $x$ direction

Solution

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