Standard electrode potential for the cell with cell reaction Zn(s) + Cu2+(aq) $\to$ Zn2+(aq) + Cu(s) is 1.1 V. Calculate the standard Gibbs energy change for the cell reaction. (Given F = 96487 C mol$-$1)

Question

Standard electrode potential for the cell with cell reaction

Zn(s) + Cu²⁺(aq) $\to$ Zn²⁺(aq) + Cu(s)

is 1.1 V. Calculate the standard Gibbs energy change for the cell reaction. (Given F = 96487 C mol^$-$1)

$-$200.27 J mol^$-$1

$-$200.27 kJ mol^$-$1

$-$212.27 kJ mol^$-$1

$-$212.27 J mol^$-$1

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