Phosphorus pentachloride dissociates as follows, in a closed reaction vessel PCl5 (g) $\leftrightharpoons$ PCl3 (g) + Cl2 (g) If total pressure at equilibrium of the reaction mixture is P and degree of dissociation of PCl5 is x, the partial pressure of PCl3 will be

Question

Phosphorus pentachloride dissociates as follows, in a closed reaction vessel
PCl₅ (g) $\leftrightharpoons$ PCl₃ (g) + Cl₂ (g)
If total pressure at equilibrium of the reaction mixture is P and degree of dissociation of PCl₅ is x, the partial pressure of PCl₃ will be

$\left( {{x \over {x + 1}}} \right)P$

$\left( {{2x \over {1 - x}}} \right)P$

$\left( {{x \over {x - 1}}} \right)P$

$\left( {{x \over {1 - x}}} \right)P$

Solution

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