Question
The percentage error in the measurement of g is : (Given that $g = {{4{\pi ^2}L} \over {{T^2}}}$, $L = (10\, \pm \,0.1)$ cm, $T = (100\, \pm \,1)$ s)
The percentage error in the measurement of g is : (Given that $g = {{4{\pi ^2}L} \over {{T^2}}}$, $L = (10\, \pm \,0.1)$ cm, $T = (100\, \pm \,1)$ s)