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Question

The sliding contact C is at one fourth of the length of the potentiometer wire (AB) from A as shown in the circuit diagram. If the resistance of the wire AB is R0, then the potential drop (V) across the resistor R is

${{2{V_0}R} \over {2{R_0} + 3R}}$
${{4{V_0}R} \over {3{R_0} + 16R}}$
${{4{V_0}R} \over {3{R_0} + R}}$
${{2{V_0}R} \over {4{R_0} + R}}$

Solution

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