If ${{a_1},{a_2},....{a_n}}$ are in H.P., then the expression ${{a_1}\,{a_2} + \,{a_2}\,{a_3}\, + .... + {a_{n - 1}}\,{a_n}}$ is equal to

Question

$n({a_1}\, - {a_n})$

$(n - 1)({a_1}\, - {a_n})$

$n{a_1}{a_n}$

$(n - 1)\,\,{a_1}{a_n}$

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