If the lines $3x - 4y - 7 = 0$ and $2x - 3y - 5 = 0$ are two diameters of a circle of area $49\pi $ square units, the equation of the circle is :

Question

$\,{x^2} + {y^2} + 2x\, - 2y - 47 = 0\,$

$\,{x^2} + {y^2} + 2x\, - 2y - 62 = 0\,$

${x^2} + {y^2} - 2x\, + 2y - 62 = 0$

${x^2} + {y^2} - 2x\, + 2y - 47 = 0$

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