A triangular park is enclosed on two sides by a fence and on the third side by a straight river bank. The two sides having fence are of same length $x$. The maximum area enclosed by the park is
${3 \over 2}{x^2}$
$\sqrt {{{{x^3}} \over 8}} $
${1 \over 2}{x^2}$
$\pi {x^2}$
Solution
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