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Question
The potential energy of a $1$ $kg$ particle free to move along the $x$-axis is given by $V\left( x \right) = \left( {{{{x^4}} \over 4} - {{{x^2}} \over 2}} \right)J$.

The total mechanical energy of the particle is $2J.$ Then, the maximum speed (in $m/s$) is

${3 \over {\sqrt 2 }}$
${\sqrt 2 }$
${1 \over {\sqrt 2 }}$
$2$

Solution

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