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Question
If the binding energy per nucleon in ${}_3^7Li$ and ${}_2^4He$ nuclei are $5.60$ $MeV$ and $7.06$ $MeV$ respectively, then in the reaction $$p + {}_3^7Li \to 2\,{}_2^4He$$
energy of proton must be
$28.24$ $MeV$
$17.28$ $MeV$
$1.46$ $MeV$
$39.2$ $MeV$

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