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Question

What mass of 95% pure CaCO3 will be required to neutralise 50 mL of 0.5 M HCl solution according to the following reaction?

CaCO3(s) + 2HCl(aq) $\to$ CaCl2(aq) + Co2(g) + 2H2O(l)

[Calculate upto second place of decimal point]

1.25 g
1.32 g
3.65 g
9.50 g

Solution

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