In a triangle $PQR,\;\;\angle R = {\pi \over 2}.\,\,If\,\,\tan \,\left( {{P \over 2}} \right)$ and $ \tan \left( {{Q \over 2}} \right)$ are the roots of $a{x^2} + bx + c = 0,\,\,a \ne 0$ then
$a = b + c$
$c = a + b$
$b = c$
$b = a + c$
Solution
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