A ball is projected with a velocity, 10 ms$-$1, at an angle of 60$^\circ$ with the vertical direction. Its speed at the highest point of its trajectory will be

Question

A ball is projected with a velocity, 10 ms^$-$1, at an angle of 60$^\circ$ with the vertical direction. Its speed at the highest point of its trajectory will be

Zero

5$\sqrt3$ ms^$-$1

5 ms^$-$1

10 ms^$-$1

Solution

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