A spherical ball of mass $20$ $kg$ is stationary at the top of a hill of height $100$ $m$. It rolls down a smooth surface to the ground, then climbs up another hill of height $30$ $m$ and finally rolls down to a horizontal base at a height of $20$ $m$ above the ground. The velocity attained by the ball is
$20$ $m/s$
$40$ $m/s$
$10\sqrt {30} \,\,\,m/s$
$10\,\,m/s$
Solution
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