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Question
Two simple harmonic motions are represented by the equations ${y_1} = 0.1\,\sin \left( {100\pi t + {\pi \over 3}} \right)$ and ${y_2} = 0.1\,\cos \,\pi t.$ The phase difference of the velocity of particle $1$ with respect to the velocity of particle $2$ is
${\pi \over 3}$
${{ - \pi } \over 6}$
${\pi \over 6}$
${{ - \pi } \over 3}$

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