A charged particle of mass $m$ and charge $q$ travels on a circular path of radius $r$ that is perpendicular to a magnetic field $B.$ The time taken by the particle to complete one revolution is
${{2\pi {q^2}B} \over m}$
${{2\pi mq} \over B}$
${{2\pi m} \over {qB}}$
${{2\pi qB} \over m}$
Solution
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