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Question
A capacitor of capacitance 'C', is connected across an ac source of voltage V, given by

V = V0sin$\omega$t

The displacement current between the plates of the capacitor, would then be given by :
${I_d} = {V_0}\omega C\sin \omega t$
${I_d} = {V_0}\omega C\cos \omega t$
${I_d} = {{{V_0}} \over {\omega C}}\cos \omega t$
${I_d} = {{{V_0}} \over {\omega C}}\sin \omega t$

Solution

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