A particle is released from height S from the surface of the Earth. At a certain height its kinetic energy is three times its potential energy. The height from the surface of earth and the speed of the particle at that instant are respectively -

Question

${S \over 4},\sqrt {{{3gS} \over 2}} $

${S \over 4},{{3gS} \over 2}$

${S \over 4},{{\sqrt {3gS} } \over 2}$

${S \over 2},{{\sqrt {3gS} } \over 2}$

Solution

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