An electromagnetic wave of wavelength '$\lambda$' is incident on a photosensitive surface of negligible work function. If 'm' mass is of photoelectron emitted from the surface has de-Broglie wavelength $\lambda$d, then :

Question

An electromagnetic wave of wavelength '$\lambda$' is incident on a photosensitive surface of negligible work function. If 'm' mass is of photoelectron emitted from the surface has de-Broglie wavelength $\lambda$_d, then :

$\lambda = \left( {{{2h} \over {mc}}} \right){\lambda _d}^2$

$\lambda = \left( {{{2m} \over {hc}}} \right){\lambda _d}^2$

${\lambda _d} = \left( {{{2mc} \over h}} \right){\lambda ^2}$

$\lambda = \left( {{{2mc} \over h}} \right){\lambda _d}^2$

Solution

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