A particle of mass 'm' is projected with a velocity $\upsilon $ = kVe = (k < 1) from the surface of the earth. (Ve = escape velocity)The maximum height above the surface reached by the particle is :

Question

A particle of mass 'm' is projected with a velocity $\upsilon $ = kV_e = (k < 1) from the surface of the earth. (V_e = escape velocity)

The maximum height above the surface reached by the particle is :

${{R{k^2}} \over {1 - {k^2}}}$

$R{\left( {{k \over {1 - {k^2}}}} \right)^2}$

$R{\left( {{k \over {1 + {k^2}}}} \right)^2}$

${{{R^2}k} \over {1 + k}}$

Solution

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