If the lines 2x + 3y + 1 + 0 and 3x - y - 4 = 0 lie along diameter of a circle of circumference $10\,\pi $, then the equation of the circle is :
${x^2}\, + \,{y^2} + \,2x\, - \,2y - \,23\,\, = 0$
${x^2}\, + \,{y^2} - \,2x\, - \,2y - \,23\,\, = 0$
${x^2}\, + \,{y^2} + \,2x\, + \,2y - \,23\,\, = 0$
${x^2}\, + \,{y^2} - \,2x\, + \,2y - \,23\,\, = 0$
