Anisole on cleavage with Hl gives : - DASH

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Anisole on cleavage with Hl gives :

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Step-by-Step Explanation Step 1: Recognize the Reactants Anisole is an aromatic ether with the structure $C_6H_5OCH_3$. Hydroiodic acid (HI) is a strong acid known to cleave ethers. Step 2: Understand the Cleavage Reaction of Ethers When an aromatic methyl ether like anisole is treated with HI, the ether bond (the $C-O$ bond) breaks. In acidic conditions, the proton ($H^+$) can protonate the ether oxygen, making it more susceptible to nucleophilic attack by the iodide ion ($I^-$). Step 3: Mechanism of Cleavage Protonation: The oxygen of anisole is protonated by HI, forming an oxonium ion ($C_6H_5OCH_3H^+$). Nucleophilic Attack: The iodide ion ($I^-$) attacks the methyl group, leading to the cleavage of the $C-O$ bond. Product Formation: This cleavage yields phenol ($C_6H_5OH$) and methyl iodide ($CH_3I$). The overall reaction is: $C_6H_5OCH_3 \;+\; HI \;\longrightarrow\; C_6H_5OH \;+\; CH_3I$ Step 4: Final Products Hence, upon cleavage with HI, anisole gives phenol and methyl iodide. The corresponding structures are shown below: Reference Solution Image This image illustrates the cleavage mechanism and product formation clearly.

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