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Question
The mean free path for a gas, with molecular diameter d and number density n can be expressed as :
${1 \over {\sqrt 2 n\pi {d^2}}}$
${1 \over {\sqrt 2 {n^2}\pi {d^2}}}$
${1 \over {\sqrt 2 {n^2}{\pi ^2}{d^2}}}$
${1 \over {\sqrt 2 n\pi d}}$

Solution

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