The capacitance of a parallel plate capacitor with air as medium is 6$\mu $F. With the introduction of a dielectric medium, the capacitance become 30 $\mu $F The permittivity of the medium is :$\left( {{\varepsilon _0} = 8.85 \times {{10}^{ - 12}}{C^2}{N^{ - 1}}{m^{ - 2}}} \right)$

Question

The capacitance of a parallel plate capacitor with air as medium is 6$\mu $F. With the introduction of a dielectric medium, the capacitance become 30 $\mu $F The permittivity of the medium is :
$\left( {{\varepsilon _0} = 8.85 \times {{10}^{ - 12}}{C^2}{N^{ - 1}}{m^{ - 2}}} \right)$

$1.77 \times {10^{ - 12}}{C^2}{N^{ - 1}}{m^{ - 2}}$

$0.44 \times {10^{ - 10}}{C^2}{N^{ - 1}}{m^{ - 2}}$

$5.00{C^2}{N^{ - 1}}{m^{ - 2}}$

$0.44 \times {10^{ - 13}}{C^2}{N^{ - 1}}{m^{ - 2}}$

Solution

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