The electrochemical equivalent of a metal is ${3.35109^{ - 7}}$ $kg$ per Coulomb. The mass of the metal liberated at the cathode when a $3A$ current is passed for $2$ seconds will be
$6.6 \times {10^{57}}/kg$
$9.9 \times {10^{ - 7}}\,kg$
$19.8 \times {10^{ - 7}}\,kg$
$1.1 \times {10^{ - 7}}\,kg$
Solution
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