A metal conductor of length $1$ $m$ rotates vertically about one of its ends at angular velocity $5$ radians per second. If the horizontal component of earth's magnetic field is $0.2 \times {10^{ - 4}}T,$ then the $e.m.f.$ developed between the two ends of the conductor is
$5mV$
$50\mu V$
$5\mu V$
$50mV$
Solution
Please login to view the detailed solution steps...