When an object is shot from the bottom of a long smooth inclined plane kept at an angle 60o with horizontal, it can travel a distance x1 along the plane. But when the inclination is decreased to 30o and the same object is shot with the same velocity, it can travel x2 distance. Then x1 : x2 will be :
1 : $\sqrt 2 $
$\sqrt 2 $ : 1
1 : $\sqrt 3 $
1 : 2$\sqrt 3 $
Solution
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