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Question
If ${\left( {{{1 + i} \over {1 - i}}} \right)^x} = 1$ then :
x = 2n + 1, where n is any positive integer
x = 4n , where n is any positive integer
x = 2n, where n is any positive integer
x = 4n + 1, where n is any positive integer.

Solution

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