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Question
If $f\left( x \right) = {x^n},$ then the value of

$f\left( 1 \right) - {{f'\left( 1 \right)} \over {1!}} + {{f''\left( 1 \right)} \over {2!}} - {{f'''\left( 1 \right)} \over {3!}} + ..........{{{{\left( { - 1} \right)}^n}{f^n}\left( 1 \right)} \over {n!}}$ is

$1$
${{2^n}}$
${{2^n} - 1}$
$0$

Solution

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