The escape velocity for a body projected vertically upwards from the surface of earth is $11$ $km/s.$ If the body is projected at an angle of ${45^ \circ }$ with the vertical, the escape velocity will be
$11\sqrt 2 \,\,km/s$
$22$ $km/s$
$11$ $km/s$
${{11} \over {\sqrt 2 }}km/s$
Solution
Please login to view the detailed solution steps...
