The orbital angular momentum for an electron revolving in an orbit is given by $\sqrt {l(l + 1)} {h \over {2\pi }}$. This momentum for an s-electron will be given by
zero
${h \over {2\pi }}$
$\sqrt 2 {h \over {2\pi }}$
$ + {1 \over 2}{h \over {2\pi }}$
Solution
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