Your AI-Powered Personal Tutor
Question

A block of mass m is placed on a smooth inclined wedge ABC of inclination q as shown in the figure. The wedge is given an acceleration 'a' towards the right. The relation between a and q for the block to remain stationary on the wedge is

$a = {g \over {\cos ec\theta }}$

$a = {g \over {\cos ec\theta }}$

$a = g\cos \theta $

$a = g\tan \theta $

Solution

Please login to view the detailed solution steps...

Go to DASH