If $\alpha \ne \beta $ but ${\alpha ^2} = 5\alpha - 3$ and ${\beta ^2} = 5\beta - 3$ then the equation having $\alpha /\beta $ and $\beta /\alpha \,\,$ as its roots is
$3{x^2} - 19x + 3 = 0$
$3{x^2} + 19x - 3 = 0$
$3{x^2} - 19x - 3 = 0$
${x^2} - 5x + 3 = 0$
Solution
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