If $y = {\left( {x + \sqrt {1 + {x^2}} } \right)^n},$ then $\left( {1 + {x^2}} \right){{{d^2}y} \over {d{x^2}}} + x{{dy} \over {dx}}$ is - DASH

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Question

If $y = {\left( {x + \sqrt {1 + {x^2}} } \right)^n},$ then $\left( {1 + {x^2}} \right){{{d^2}y} \over {d{x^2}}} + x{{dy} \over {dx}}$ is

${n^2}y$

$-{n^2}y$

$-y$

$2{x^2}y$

Solution

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