${\cot ^{ - 1}}\left( {\sqrt {\cos \alpha } } \right) - {\tan ^{ - 1}}\left( {\sqrt {\cos \alpha } } \right) = x,$ then sin x is equal to :

Question

${\tan ^2}\left( {{\alpha \over 2}} \right)$

${\cot ^2}\left( {{\alpha \over 2}} \right)$

$\tan \alpha $

$cot\left( {{\alpha \over 2}} \right)$

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