The maximum distance from origin of a point on the curve $x = a\sin t - b\sin \left( {{{at} \over b}} \right)$ $y = a\cos t - b\cos \left( {{{at} \over b}} \right),$ both $a,b > 0$ is

Question

The maximum distance from origin of a point on the curve
$x = a\sin t - b\sin \left( {{{at} \over b}} \right)$
$y = a\cos t - b\cos \left( {{{at} \over b}} \right),$ both $a,b > 0$ is

$a-b$

$a+b$

$\sqrt {{a^2} + {b^2}} $

$\sqrt {{a^2} - {b^2}} $

Solution

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