$\int_{ - \pi }^\pi {{{2x\left( {1 + \sin x} \right)} \over {1 + {{\cos }^2}x}}} dx$ is - DASH

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Question

$\int_{ - \pi }^\pi {{{2x\left( {1 + \sin x} \right)} \over {1 + {{\cos }^2}x}}} dx$ is

${{{\pi ^2}} \over 4}$

${{\pi ^2}}$

zero

${\pi \over 2}$

Solution

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