The solution of the equation $\,{{{d^2}y} \over {d{x^2}}} = {e^{ - 2x}}$

Question

${{{e^{ - 2x}}} \over 4}$

${{{e^{ - 2x}}} \over 4} + cx + d$

${1 \over 4}{e^{ - 2x}} + c{x^2} + d$

$\,{1 \over 4}{e^{ - 4x}} + cx + d$

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