$A$ and $B$ are events such that $P\left( {A \cup B} \right) = 3/4$,$P\left( {A \cap B} \right) = 1/4,$ $P\left( {\overline A } \right) = 2/3$ then $P\left( {\overline A \cap B} \right)$ is :

Question

$A$ and $B$ are events such that $P\left( {A \cup B} \right) = 3/4$,$P\left( {A \cap B} \right) = 1/4,$
$P\left( {\overline A } \right) = 2/3$ then $P\left( {\overline A \cap B} \right)$ is :

$5/12$