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Question
The number of electrons delivered at the cathode during electrolysis by a current of 1 ampere in 60 seconds is (charge on electron = 1.60 $ \times $ 10$-$19C)
6 $ \times $ 1023
6 $ \times $ 1020
3.75 $ \times $ 1020
7.48 $ \times $ 1023

Solution

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