Two rotating bodies A and B of masses m and 2m with moments of inertia ${I_A}$ and ${I_B}$ (${I_B}$ > ${I_A}$) have equal kinetic energy of rotation. If LA and LB be their angular momenta respectively, then

Question

Two rotating bodies A and B of masses m and 2m with moments of inertia ${I_A}$ and ${I_B}$ (${I_B}$ > ${I_A}$) have equal kinetic energy of rotation. If L_A and L_B be their angular momenta respectively, then

${L_A} = {{{L_B}} \over 2}$

${L_A} = 2{L_B}$

${L_B} > {L_A}$

${L_A} > {L_B}$

Solution

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