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Question
Consider the following liquid-vapour equilibrium.
Liquid $\rightleftharpoons$ Vapour
Which of the following relations is correct ?
${{d\ln P} \over {d{T^2}}} = {{ - \Delta {H_v}} \over {{T^2}}}$
${{d\ln P} \over {dT}} = {{\Delta {H_v}} \over {R{T^2}}}$
${{d\ln G} \over {d{T^2}}} = {{\Delta {H_v}} \over {R{T^2}}}$
${{d\ln P} \over {dT}} = {{ - \Delta {H_v}} \over {RT}}$

Solution

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