If the velocity of a particle is v = At + Bt2, where A and B are constants, then the distance travelled by it between 1 s and 2 s is

Question

If the velocity of a particle is v = At + Bt², where A and B are constants, then the distance travelled by it between 1 s and 2 s is

${3 \over 2}A + {7 \over 3}B$

${A \over 2} + {B \over 3}$

${3 \over 2}A + 4B$

$3A + 7B$

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