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Question
A particle of unit mass undergoes one-dimensional motion such that its velocity varies according to $v\left( x \right) = \beta {x^{ - 2n}}$, where $\beta $ and n are constants and x is the position of the particle. The acceleration of the particle as a function of x, is given by
$ - 2{\beta ^2}{x^{ - 2n + 1}}$
$ - 2n{\beta ^2}{e^{ - 4n + 1}}$
$ - 2n{\beta ^2}{x^{ - 2n - 1}}$
$ - 2n{\beta ^2}{x^{ - 4n - 1}}$

Solution

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